5 câu Trắc nghiệm Tính chất của dãy tỉ số bằng nhau có đáp án (Nhận biết)

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{\text{ac}}{\text{bd}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{\text{a : c}}{\text{b : d}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{\text{a}-\text{c}}{\text{d}-\text{b}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{\text{a + c}}{\text{b + d}}$.

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}+\text{c}+\text{e}}{\text{b}+\text{d}+\text{f}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}-\text{c}-\text{e}}{\text{b}+\text{d}+\text{f}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}+\text{c}+\text{e}}{\text{b}-\text{d}-\text{f}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}+\text{c}-\text{e}}{\text{b}-\text{d}+\text{f}}$.

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}+\text{c}+\text{e}}{\text{b}+\text{d}+\text{f}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}+\text{c}-\text{e}}{\text{b}+\text{d}-\text{f}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}-\text{c}+\text{e}}{\text{b}-\text{d}+\text{f}}$;

$\frac{a}{b}$ = $\frac{c}{d}$ = $\frac{e}{f}$ = $\frac{\text{a}+\text{c}+\text{e}}{\text{b}-\text{d}-\text{f}}$.

$\frac{x}{2}$ = $\frac{y}{3}$ = $\frac{z}{4}$ = $\frac{\text{x}+\text{y}+\text{z}}{9}$;

$\frac{x}{2}$ = $\frac{y}{3}$ = $\frac{z}{4}$ = $\frac{\text{x}-\text{y}+\text{z}}{9}$;

$\frac{x}{2}$ = $\frac{y}{3}$ = $\frac{z}{4}$ = $\frac{\text{x}-\text{y}+\text{z}}{3}$;

$\frac{x}{2}$ = $\frac{y}{3}$ = $\frac{z}{4}$ = $\frac{\text{x}+\text{y}-\text{z}}{1}$.