Xác định lim x → 0 | x |/ x ^2 .
Giải thích
Chọn C
Ta có \(\mathop {\lim }\limits_{x \to {0^ + }} \frac{{\left| x \right|}}{{{x^2}}} = \mathop {\lim }\limits_{x \to {0^ + }} \frac{x}{{{x^2}}} = \mathop {\lim }\limits_{x \to {0^ + }} \frac{1}{x} = + \infty \).
\(\mathop {\lim }\limits_{x \to {0^ - }} \frac{{\left| x \right|}}{{{x^2}}} = \mathop {\lim }\limits_{x \to {0^ - }} \frac{{ - x}}{{{x^2}}} = \mathop {\lim }\limits_{x \to {0^ - }} \frac{{ - 1}}{x} = + \infty \).
Vậy không tồn tại \(\mathop {\lim }\limits_{x \to 0} \frac{{\left| x \right|}}{{{x^2}}}\).