Urani 92^238 U sau nhiều lần phóng xạ
Giải thích
\(\frac{{{m_{Pb}}}}{{{m_U}}} = \frac{{{A_{Pb}}}}{{{A_U}}} \cdot \frac{{\Delta N}}{N} = \frac{{{A_{Pb}}}}{{{A_U}}} \cdot \frac{{{N_0}\left( {1 - {2^{\frac{{ - t}}{T}}}} \right)}}{{{N_0} \cdot {2^{\frac{{ - t}}{T}}}}} = \frac{{{A_{Pb}}}}{{{A_U}}} \cdot \left( {{2^{\frac{t}{T}}} - 1} \right) \Rightarrow \frac{1}{{37}} = \frac{{206}}{{238}} \cdot \left( {{2^{\frac{t}{{4,{{6.10}^9}}}}} - 1} \right) \Rightarrow t \approx {2.10^8}{\rm{ }}\)năm