Tính z = (2 + 3 i) /(3 − i)

\[\frac{3}{5} - \frac{{\rm{i}}}{2}\]

\[\frac{1}{2} - \frac{{{\rm{3i}}}}{2}\]

\[\frac{1}{{10}} - \frac{{{\rm{5i}}}}{2}\]

\[\frac{3}{{10}} - \frac{{{\rm{11i}}}}{{10}}\]