Tính V?

${}_{{\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6}=\frac{20.90}{100}=18\mathrm{g}\Rightarrow {\mathrm{n}}_{{\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6}=\frac{18}{180}=0,1\mathrm{mol}$

C₆H₁₂O₆    2C₂H₅OH + 2CO₂

    0,1                           0,2mol

Hiệu suất phản ứng là 95%

$\Rightarrow {\mathrm{n}}_{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}=0,2.95\mathrm{\%}=0,19\mathrm{mol}\Rightarrow {\mathrm{m}}_{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}=0,19.46=8,74\mathrm{g}$

${\mathrm{V}}_{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}=\frac{8,74}{0,8}=10,925\mathrm{mL}\Rightarrow {{\mathrm{V}}_{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}}_{{46}^0}=\frac{10,925.100}{46}=23,75\mathrm{mL}$