Tính sin α .
Giải thích
A
\[\frac{{\sin 2\alpha + \sin 5\alpha - \sin 3\alpha }}{{2{{\cos }^2}2\alpha + \cos \alpha - 1}} = - 2\]
\[ \Leftrightarrow \frac{{2\sin \alpha \cos \alpha + 2\cos 4\alpha \sin \alpha }}{{2.\frac{{1 + \cos 4\alpha }}{2} + \cos \alpha - 1}} = - 2\]
\[ \Leftrightarrow \frac{{2\sin \alpha \cos \alpha + 2\cos 4\alpha \sin \alpha }}{{\cos 4\alpha + \cos \alpha }} = - 2\]
\[ \Leftrightarrow \frac{{2\sin \alpha \left( {\cos \alpha + \cos 4\alpha } \right)}}{{\cos 4\alpha + \cos \alpha }} = - 2\]
\[ \Leftrightarrow 2\sin \alpha = - 2\]
\[ \Leftrightarrow \sin \alpha = - 1\].