Tính lim x → + ∞ x 2 − x + 1 2 − x .
Giải thích
D
\(\mathop {\lim }\limits_{x \to + \infty } \frac{{{x^2} - x + 1}}{{2 - x}}\)\[ = \mathop {\lim }\limits_{x \to + \infty } \frac{{{x^2}\left( {1 - \frac{1}{x} + \frac{1}{{{x^2}}}} \right)}}{{x\left( {\frac{2}{x} - 1} \right)}} = - \infty \].