Tính lim n → + ∞ ( n ^2 − n + 3 ) .
Giải thích
\(\mathop {\lim }\limits_{n \to + \infty } \left( {{n^2} - n + 3} \right) = \mathop {\lim }\limits_{n \to + \infty } {n^2}\left( {1 - \frac{1}{n} + \frac{3}{{{n^2}}}} \right) = + \infty \)
\(\mathop {\lim }\limits_{n \to + \infty } \left( {{n^2} - n + 3} \right) = \mathop {\lim }\limits_{n \to + \infty } {n^2}\left( {1 - \frac{1}{n} + \frac{3}{{{n^2}}}} \right) = + \infty \)