Tính lim n → + ∞ (2n^2 + 1)/( 3n ^2 + n ).
Giải thích
\(\mathop {\lim }\limits_{n \to + \infty } \frac{{2{n^2} + 1}}{{3{n^2} + n}} = \mathop {\lim }\limits_{n \to + \infty } \frac{{2 + \frac{1}{{{n^2}}}}}{{3 + \frac{1}{n}}} = \frac{2}{3}\)
\(\mathop {\lim }\limits_{n \to + \infty } \frac{{2{n^2} + 1}}{{3{n^2} + n}} = \mathop {\lim }\limits_{n \to + \infty } \frac{{2 + \frac{1}{{{n^2}}}}}{{3 + \frac{1}{n}}} = \frac{2}{3}\)