Tính giới hạn lim x → 1 √ 10 − x^2 − 3 / 1 − x 2 .

\(\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt {10 - {x^2}} - 3}}{{1 - {x^2}}}\)\[ = \mathop {\lim }\limits_{x \to 1} \frac{{1 - {x^2}}}{{\left( {1 - {x^2}} \right)\left( {\sqrt {10 - {x^2}} + 3} \right)}}\]\[ = \mathop {\lim }\limits_{x \to 1} \frac{1}{{\sqrt {10 - {x^2}} + 3}} = \frac{1}{6}\]. Chọn B.