Tính f ′′ ( − 1 ) .
Giải thích
A
\(f'\left( x \right) = \frac{{ - 2}}{{{{\left( {2x - 1} \right)}^2}}}\), \(f''\left( x \right) = \frac{8}{{{{\left( {2x - 1} \right)}^3}}}\).
Khi đó \(f''\left( { - 1} \right) = - \frac{8}{{27}}\).
A
\(f'\left( x \right) = \frac{{ - 2}}{{{{\left( {2x - 1} \right)}^2}}}\), \(f''\left( x \right) = \frac{8}{{{{\left( {2x - 1} \right)}^3}}}\).
Khi đó \(f''\left( { - 1} \right) = - \frac{8}{{27}}\).