Bộ 20 đề thi cuối kì 2 Toán lớp 4 Chân trời sáng tạo có đáp án - Đề 9

Tính bằng cách thuận tiện.

11/11

Tính bằng cách thuận tiện. (1 điểm)

\(\frac{5}{8}\,\, + \,\,\frac{6}{7}\,\, + \,\,\frac{1}{7}\,\, + \,\,\frac{3}{8}\)

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\(\frac{{56}}{{11}}\,\, \times \,\,\frac{9}{7}\,\, + \,\,\frac{9}{7}\,\, \times \,\,\frac{{21}}{{11}}\)

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Giải thích

\(\frac{5}{8}\,\, + \,\,\frac{6}{7}\,\, + \,\,\frac{1}{7}\,\, + \,\,\frac{3}{8}\)

\( = \left( {\frac{5}{8}\,\, + \,\,\frac{3}{8}} \right)\,\, + \left( {\frac{6}{7}\,\, + \,\,\frac{1}{7}} \right)\,\,\)

\( = \frac{{5 + 3}}{8}\,\, + \frac{{6 + 1}}{7}\)

\( = \frac{8}{8}\,\, + \frac{7}{7}\)

= 1 + 1

= 2

\(\frac{{56}}{{11}}\,\, \times \,\,\frac{9}{7}\,\, + \,\,\frac{9}{7}\,\, \times \,\,\frac{{21}}{{11}}\)

\( = \frac{9}{7} \times \left( {\frac{{56}}{{11}}\,\,\, + \,\,\,\,\frac{{21}}{{11}}} \right)\)

\( = \frac{9}{7} \times \frac{{56 + 21}}{{11}}\)

\( = \frac{9}{7} \times \frac{{77}}{{11}}\)

\( = \frac{9}{{\not 7}} \times \frac{{\not 7 \times \not 11}}{{\not 11}}\)

= 9