Tính bằng cách thuận tiện a) 3/5 + 14/7 + 4/10 = b) 1/7 + 2/7 + 3/7 + 4/7 + 5/7 + 6/7

a) \(\frac{3}{5}\) + \(\frac{{14}}{7}\) + \(\frac{4}{{10}}\)

= (\(\frac{3}{5}\) + \(\frac{4}{{10}}\)) + \(\frac{{14}}{7}\)

= 1 + 2

= 3

b) \(\frac{1}{7}\) + \(\frac{2}{7}\) + \(\frac{3}{7}\)+ \(\frac{4}{7}\) + \(\frac{5}{7}\) + \(\frac{6}{7}\)

= \(\frac{{1 + 2 + 3 + 4 + 5 + 6}}{7}\)

= \(\frac{{21}}{7}\)

= 3