Tính B = 2^2/3 ⋅ 3^2/8 ⋅ 4^2/15 ⋅ 5^2/24 ⋅ 6^2/35 ⋅ 7^2/48 ⋅ 8^2/63 ⋅ 9^2/80 ta được

7/27

Tính \[B = \frac{{{2^2}}}{3} \cdot \frac{{{3^2}}}{8} \cdot \frac{{{4^2}}}{{15}} \cdot \frac{{{5^2}}}{{24}} \cdot \frac{{{6^2}}}{{35}} \cdot \frac{{{7^2}}}{{48}} \cdot \frac{{{8^2}}}{{63}} \cdot \frac{{{9^2}}}{{80}}\] ta được

\[\frac{9}{5}\]

\[\frac{3}{5}\]

\[\frac{6}{5}\]

Giải thích

\[B = \frac{{{2^2}}}{3} \cdot \frac{{{3^2}}}{8} \cdot \frac{{{4^2}}}{{15}} \cdot \frac{{{5^2}}}{{24}} \cdot \frac{{{6^2}}}{{35}} \cdot \frac{{{7^2}}}{{48}} \cdot \frac{{{8^2}}}{{63}} \cdot \frac{{{9^2}}}{{80}}\]

\[ = \frac{{2.2}}{{1.3}} \cdot \frac{{3.3}}{{2.4}} \cdot \frac{{4.4}}{{3.5}} \cdot \frac{{5.5}}{{4.6}} \cdot \frac{{6.6}}{{5.7}} \cdot \frac{{7.7}}{{6.8}} \cdot \frac{{8.8}}{{7.9}} \cdot \frac{{9.9}}{{8.10}}\]

\[ = \frac{{2.3.4.5.6.7.8.9}}{{1.2.3.4.5.6.7.8.}} \cdot \frac{{2.3.4.5.6.7.8.9}}{{3.4.5.6.7.8.9.10}}\]

\[ = \frac{9}{1} \cdot \frac{2}{{10}} = \frac{{9.2}}{{1.10}} = \frac{9}{5}\]

Đáp án cần chọn là: A