Tính: a) (-73) + 0 b) |-18| + (-12) c) 102 + (-120)
Giải thích
a) (–73) + 0 = –73;
b) |–18| + (–12) = 18 + (–12) = 18 – 12 = 6;
c) 102 + (–120) = – (120 – 102) = –18.
a) (–73) + 0 = –73;
b) |–18| + (–12) = 18 + (–12) = 18 – 12 = 6;
c) 102 + (–120) = – (120 – 102) = –18.