Bài tập Toán lớp 2 Phép trừ (có nhớ) trong phạm vi 100 (có đáp án)

tính 33 - 14

Giải thích

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{33}\\{14}\end{array}} \\\,\,\,\,19\end{array}\)

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{41}\\{28}\end{array}} \\\,\,\,\,13\end{array}\)

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{80}\\{72}\end{array}} \\\,\,\,\,\,\,\,8\end{array}\)

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{61}\\{33}\end{array}} \\\,\,\,\,28\end{array}\)

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{38}\\{19}\end{array}} \\\,\,\,\,19\end{array}\)

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{84}\\{48}\end{array}} \\\,\,\,\,36\end{array}\)

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{65}\\{28}\end{array}} \\\,\,\,\,37\end{array}\)

\(\begin{array}{l}\underline { - \begin{array}{*{20}{c}}{61}\\{19}\end{array}} \\\,\,\,\,42\end{array}\)