tìm x biết x-2/5=7/10
Giải thích
Hướng dẫn giải
a) \(x - \frac{2}{5} = \frac{7}{{10}}\) \(x = \frac{7}{{10}} + \frac{2}{5}\) \(x = \frac{7}{{10}} + \frac{4}{{10}}\) \(x = \frac{{11}}{{10}}\). Vậy \(x = \frac{{11}}{{10}}\). | b) \(\left( {2x - \frac{2}{3}} \right) \cdot \frac{5}{6} = \frac{5}{{18}}\) \(\left( {2x - \frac{2}{3}} \right) = \frac{5}{{18}}:\frac{5}{6}\) \(\left( {2x - \frac{2}{3}} \right) = \frac{5}{{18}} \cdot \frac{6}{5}\) \(2x - \frac{2}{3} = \frac{1}{3}\) \(2x = \frac{1}{3} + \frac{2}{3}\) \(2x = 1\) \(x = 1:2\) \(x = \frac{1}{2}.\) Vậy \(x = \frac{1}{2}.\) | c) \(1,5\left( {x - 3,4} \right) = 22,5\) \(\left( {x - 3,4} \right) = 22,5:1,5\) \(x - 3,4 = 15\) \(x = 15 + 3,4\) \(x = 18,4\). |