Tìm x , biết: h) 2^( x + 4 )− 12^(.2 x − 2) = 26 ;
Giải thích
h) \({2^{x + 4}} - {12.2^{x - 2}} = 26\)
\({16.2^x} - \frac{{12}}{4}{.2^x} = 26\)
\({2^x}\left( {16 - 3} \right) = 26\)
\({13.2^x} = 26\)
\({2^x} = 2\)
\(x = 1\)
Vậy \(x = 1\).
h) \({2^{x + 4}} - {12.2^{x - 2}} = 26\)
\({16.2^x} - \frac{{12}}{4}{.2^x} = 26\)
\({2^x}\left( {16 - 3} \right) = 26\)
\({13.2^x} = 26\)
\({2^x} = 2\)
\(x = 1\)
Vậy \(x = 1\).