tìm tích phân 3 mũ x-1 /2
Giải thích
\(\int {\frac{{{3^{x - 1}}}}{2}} \;{\rm{d}}x = \frac{1}{2}\int {\frac{{{3^x}}}{3}} \;{\rm{d}}x = \frac{1}{6}\int {{3^x}} \;{\rm{d}}x = \frac{{{3^x}}}{{6\ln 3}} + C\).
\(\int {\frac{{{3^{x - 1}}}}{2}} \;{\rm{d}}x = \frac{1}{2}\int {\frac{{{3^x}}}{3}} \;{\rm{d}}x = \frac{1}{6}\int {{3^x}} \;{\rm{d}}x = \frac{{{3^x}}}{{6\ln 3}} + C\).