Tìm tích phân (2/cos^2 x-1/sin^2 x) dx
Giải thích
\(\int {\left( {\frac{1}{{{{\cos }^2}x}} - \frac{1}{{{{\sin }^2}x}}} \right)} {\rm{d}}x = \tan x + \cot x + C{\rm{. }}\)
\(\int {\left( {\frac{1}{{{{\cos }^2}x}} - \frac{1}{{{{\sin }^2}x}}} \right)} {\rm{d}}x = \tan x + \cot x + C{\rm{. }}\)