Tích số cos10°×cos30°×cos50°×cos70° bằng
Hướng dẫn giải:
Đáp án đúng là: C
cos10°×cos30°×cos50°×cos70°
= \(cos10^\circ \cdot cos30^\circ \cdot \frac{1}{2}\left[ {cos\left( {50^\circ - 70^\circ } \right) + cos\left( {50^\circ + 70^\circ } \right)} \right]\)
\( = cos10^\circ \cdot \frac{{\sqrt 3 }}{2} \cdot \frac{1}{2}\left( {cos20^\circ + cos120^\circ } \right)\)
\( = cos10^\circ \cdot \frac{{\sqrt 3 }}{2} \cdot \frac{1}{2}\left( {cos20^\circ - \frac{1}{2}} \right)\)
\( = \frac{{\sqrt 3 }}{4}cos10^\circ \left( {cos20^\circ - \frac{1}{2}} \right)\)
\( = \frac{{\sqrt 3 }}{4}cos10^\circ cos20^\circ - \frac{{\sqrt 3 }}{8}cos10^\circ \)
\( = \frac{{\sqrt 3 }}{4} \cdot \frac{1}{2}\left[ {cos\left( {10^\circ - 20^\circ } \right) + cos\left( {10^\circ + 20^\circ } \right)} \right] - \frac{{\sqrt 3 }}{8}cos10^\circ \)\( = \frac{{\sqrt 3 }}{4} \cdot \frac{1}{2}\left( {cos10^\circ + cos30^\circ } \right) - \frac{{\sqrt 3 }}{8}cos10^\circ \)
\( = \frac{3}{{16}}\).