Thực hiện phép tính (hợp lí nếu có thể): 14/23(-8/11)+14/23x(-3/11)
Hướng dẫn giải
1.1.
a) \(\frac{{14}}{{23}} \cdot \left( { - \frac{8}{{11}}} \right) + \frac{{14}}{{23}} \cdot \left( { - \frac{3}{{11}}} \right)\) \( = \frac{{14}}{{23}} \cdot \left( { - \frac{8}{{11}} - \frac{3}{{11}}} \right)\) \( = \frac{{14}}{{23}} \cdot \left( { - 1} \right)\) \( = \frac{{ - 14}}{{23}} \cdot \) | b) \(9,51 \cdot \left( { - 14,75} \right) + 9,51 \cdot \left( { - 85,25} \right)\) \( = 9,51 \cdot \left( { - 14,75 - 85,25} \right)\) \( = 9,51 \cdot \left( { - 100} \right)\) \( = - 951.\) |
1.2.
a) \(x - \frac{7}{4} = \frac{3}{{16}}\) \(x = \frac{3}{{16}} + \frac{7}{4}\) \(x = \frac{3}{{16}} + \frac{{28}}{{16}}\) \(x = \frac{{31}}{{16}}\). Vậy \(x = \frac{{31}}{{16}}\). | b) \(\left( {5x - \frac{4}{9}} \right) \cdot \frac{8}{{27}} = \frac{8}{3}\) \(5x - \frac{4}{9} = \frac{8}{3}:\frac{8}{{27}}\) \(5x - \frac{4}{9} = \frac{8}{3} \cdot \frac{{27}}{8}\) \(5x - \frac{4}{9} = 9\) \(5x = 9 + \frac{4}{9}\) \(5x = \frac{{85}}{9}\) \(x = \frac{{85}}{9}:5\) \(x = \frac{{17}}{9}\) Vậy \(x = \frac{{17}}{9}\). |