a) Đúng

b) Sai. $H = H_{0} \cdot 2^{\frac{- t}{T}} = 1, 48 \cdot 10^{9} \cdot 2^{\frac{- 10, 54}{5, 27}} = 0, 37 \cdot 10^{9} B q$

c) Sai. $H_{0} = λ N_{0} = \frac{l n 2}{T} \cdot N_{0} \Rightarrow 1, 48 \cdot 10^{9} = \frac{l n 2}{5, 27 \cdot 365 \cdot 24 \cdot 60 \cdot 60} \cdot N_{0} \Rightarrow N_{0} \approx 3, 55 \cdot 10^{17}$

$n_{0} = \frac{N_{0}}{N_{A}} = \frac{3, 55 \cdot 10^{17}}{6, 02 \cdot 10^{23}} \approx 5, 9 \cdot 10^{- 7} m o l$

$m_{0} = n_{0} M = 5, 9 \cdot 10^{- 7} \cdot 60 \approx 3, 54 \cdot 10^{- 5} g = 35, 4 μ g$

d) Đúng. $Δ N = N_{0} (1 - 2^{\frac{- t}{T}}) = 3, 55 \cdot 10^{17} \cdot (1 - 2^{\frac{- 4}{5, 27365 \cdot 24}}) \approx 2, 13 \cdot 10^{13}$

$Q = 0, 5 \cdot Δ N \cdot E \cdot \frac{S}{4 π r^{2}} = 0, 5 \cdot 2, 13 \cdot 10^{13} \cdot 2, 5 \cdot 1, 6 \cdot 10^{- 13} \cdot \frac{1, 5}{4 π \cdot 4^{2}} \approx 0, 0318 J$

$D = \frac{Q}{m} = \frac{0, 0318}{70} \approx 4, 5 \cdot 10^{- 4} G y$

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