Rút gọn biểu thức

Đáp án: \(1\)

\(B = \frac{{24}}{{15}} \cdot \frac{1}{{{4^2}}} \cdot 3 + \left( {\frac{8}{{15}} - \frac{{69}}{{60}} \cdot \frac{5}{{23}}} \right):\frac{{17}}{{42}}\)

\(B = \frac{{4 \cdot 6}}{{3 \cdot 5}} \cdot \frac{1}{{{4^2}}} \cdot 3 + \left( {\frac{8}{{15}} - \frac{{23}}{{20}} \cdot \frac{5}{{23}}} \right) \cdot \frac{{42}}{{17}}\)

\(B = \frac{3}{{10}} + \left( {\frac{8}{{15}} - \frac{1}{4}} \right) \cdot \frac{{42}}{{17}}\)

\(B = \frac{3}{{10}} + \frac{{17}}{{60}} \cdot \frac{{42}}{{17}}\)

\(B = \frac{3}{{10}} + \frac{7}{{10}}\)

\(B = 1.\)

Vậy \(B = 1.\)