Bài tập Toán lớp 4 Phép cộng phân số có đáp án

Phép cộng phân số với một số 2/5 + 3 =

6/6

PHÉP CỘNG PHÂN SỐ VỚI MỘT SỐ

Phép cộng phân số với một số 2/5 + 3 = (ảnh 1)Phép cộng phân số với một số 2/5 + 3 = (ảnh 2)

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Giải thích

\(\begin{array}{*{20}{c}}2\\\hline5\end{array}{\rm{ }} + {\rm{ }}3{\rm{ = }}\begin{array}{*{20}{c}}{17}\\\hline5\end{array}\)

\(\begin{array}{*{20}{c}}4\\\hline9\end{array}{\rm{ }} + {\rm{ }}7{\rm{ = }}\begin{array}{*{20}{c}}{67}\\\hline9\end{array}\)

\(2{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}3\\\hline8\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{19}\\\hline8\end{array}\)

\(\begin{array}{*{20}{c}}5\\\hline6\end{array}{\rm{ }} + {\rm{ }}8{\rm{ = }}\begin{array}{*{20}{c}}{53}\\\hline6\end{array}\)

\(4{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}3\\\hline{10}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{43}\\\hline{10}\end{array}\)

\(1{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}5\\\hline{18}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{23}\\\hline{18}\end{array}\)

\[\begin{array}{*{20}{c}}1\\\hline3\end{array}{\rm{ }} + {\rm{ }}7{\rm{ = }}\begin{array}{*{20}{c}}{22}\\\hline3\end{array}\]

\(\begin{array}{*{20}{c}}2\\\hline9\end{array}{\rm{ }} + {\rm{ 5 = }}\begin{array}{*{20}{c}}{47}\\\hline9\end{array}\)

\({\rm{6 }} + {\rm{ }}\begin{array}{*{20}{c}}4\\\hline{11}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{70}\\\hline{11}\end{array}\)

\(9{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}2\\\hline{13}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{119}\\\hline{13}\end{array}\)

\(\begin{array}{*{20}{c}}5\\\hline{12}\end{array}{\rm{ }} + {\rm{ }}10{\rm{ = }}\begin{array}{*{20}{c}}{125}\\\hline{12}\end{array}\)

\(1{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}3\\\hline{14}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{17}\\\hline{14}\end{array}\)

\(8{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}1\\\hline{20}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{161}\\\hline{20}\end{array}\)

\({\rm{3 }} + {\rm{ }}\begin{array}{*{20}{c}}1\\\hline8\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{25}\\\hline8\end{array}\)

\(4{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}4\\\hline{25}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{104}\\\hline{25}\end{array}\)

\(\begin{array}{*{20}{c}}7\\\hline{10}\end{array}{\rm{ }} + {\rm{ }}5{\rm{ = }}\begin{array}{*{20}{c}}{57}\\\hline{10}\end{array}\)

\(2{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}3\\\hline5\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{13}\\\hline5\end{array}\)

\(\begin{array}{*{20}{c}}5\\\hline{18}\end{array}{\rm{ }} + {\rm{ 3 = }}\begin{array}{*{20}{c}}{59}\\\hline{18}\end{array}\)

\(9{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}1\\\hline2\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{19}\\\hline2\end{array}{\rm{ }}\)

\(12{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}1\\\hline5\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{61}\\\hline5\end{array}\)

\(7{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}3\\\hline4\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{31}\\\hline4\end{array}{\rm{ }}\)

\[3{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}5\\\hline{16}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{53}\\\hline{16}\end{array}\]

\(\begin{array}{*{20}{c}}3\\\hline8\end{array}{\rm{ }} + {\rm{ }}7{\rm{ = }}\begin{array}{*{20}{c}}{59}\\\hline8\end{array}\)

\(2{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}4\\\hline9\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{22}\\\hline9\end{array}\)

\(9{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}1\\\hline3\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{28}\\\hline3\end{array}\)

\({\rm{5 }} + {\rm{ }}\begin{array}{*{20}{c}}7\\\hline{13}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{72}\\\hline{13}\end{array}\)

\(4{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}3\\\hline{10}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{43}\\\hline{10}\end{array}\)

\[\begin{array}{*{20}{c}}1\\\hline4\end{array}{\rm{ }} + {\rm{ }}8{\rm{ = }}\begin{array}{*{20}{c}}{33}\\\hline4\end{array}\]

\(11{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}2\\\hline{15}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{167}\\\hline{15}\end{array}\)

\(\begin{array}{*{20}{c}}5\\\hline8\end{array}{\rm{ }} + {\rm{ 14 = }}\begin{array}{*{20}{c}}{117}\\\hline8\end{array}\)

\(2{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}4\\\hline5\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{14}\\\hline5\end{array}{\rm{ }}\)

\[2{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}{17}\\\hline{40}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{97}\\\hline{40}\end{array}\]

\({\rm{5 }} + {\rm{ }}\begin{array}{*{20}{c}}3\\\hline{17}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{88}\\\hline{17}\end{array}\)

\(\begin{array}{*{20}{c}}1\\\hline9\end{array}{\rm{ }} + {\rm{ 1}}3{\rm{ = }}\begin{array}{*{20}{c}}{118}\\\hline9\end{array}\)

\(\begin{array}{*{20}{c}}2\\\hline7\end{array}{\rm{ }} + {\rm{ }}11{\rm{ = }}\begin{array}{*{20}{c}}{79}\\\hline7\end{array}\)

\(15{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}1\\\hline5\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{76}\\\hline5\end{array}\)

\(\begin{array}{*{20}{c}}5\\\hline{12}\end{array}{\rm{ }} + {\rm{ }}8{\rm{ = }}\begin{array}{*{20}{c}}{101}\\\hline{12}\end{array}\)

\(9{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}7\\\hline{20}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{187}\\\hline{20}\end{array}\)

\(10{\rm{ }} + {\rm{ }}\begin{array}{*{20}{c}}1\\\hline8\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{81}\\\hline8\end{array}\)

\[\begin{array}{*{20}{c}}5\\\hline6\end{array}{\rm{ }} + {\rm{ }}2{\rm{ = }}\begin{array}{*{20}{c}}{17}\\\hline6\end{array}\]

\(\begin{array}{*{20}{c}}7\\\hline{11}\end{array}{\rm{ }} + {\rm{ 4 = }}\begin{array}{*{20}{c}}{51}\\\hline{11}\end{array}\)

\({\rm{3 }} + {\rm{ }}\begin{array}{*{20}{c}}2\\\hline{17}\end{array}{\rm{ = }}\begin{array}{*{20}{c}}{53}\\\hline{17}\end{array}\)