Làm tính chia x^2-4xy+4y^2/2x^2-2xy+2y^2 :10x-20y/5x^3+5y^3
Giải thích
x2−4xy+4y22x2−2xy+2y2:10x−20y5x3+5y3=x−2y22.x2−xy+y2.5.x3+y310.x−2y
=x−2y22.x2−xy+y2.5.x+yx2−xy+y210.x−2y=x−2yx+y4
x2−4xy+4y22x2−2xy+2y2:10x−20y5x3+5y3=x−2y22.x2−xy+y2.5.x3+y310.x−2y
=x−2y22.x2−xy+y2.5.x+yx2−xy+y210.x−2y=x−2yx+y4