Khi đó: a) sin x = − √ 10/10 .
a) \(\cot x = - \sqrt 3 ,\frac{{3\pi }}{2} < x < 2\pi \).
\(\frac{1}{{{{\sin }^2}x}} = 1 + {\cot ^2}x = 1 + {( - \sqrt 3 )^2} = 10 \Rightarrow {\sin ^2}x = \frac{1}{{10}} \Rightarrow \sin x = \pm \frac{{\sqrt {10} }}{{10}}\).
\({\rm{V\`i }}\frac{{3\pi }}{2} < x < 2\pi {\rm{ n\^e n }}\sin x = - \frac{{\sqrt {10} }}{{10}}\).
b) \(\cos x = \cot x \cdot \sin x = - \sqrt 3 .\left( { - \frac{{\sqrt {10} }}{{10}}} \right) = \frac{{\sqrt {30} }}{{10}}.\)
c) \(\sin \left( {\frac{{4\pi }}{3} - x} \right) = \sin \frac{{4\pi }}{3}\cos x - \cos \frac{{4\pi }}{3}\sin x = - \frac{{\sqrt 3 }}{2} \cdot \left( {\frac{{\sqrt {30} }}{{10}}} \right) - \frac{{ - 1}}{2} \cdot \frac{{ - \sqrt {10} }}{{10}} = \frac{{ - \sqrt {10} }}{5}\).
c) \(\tan x = \frac{1}{{\cot x}} = - \frac{{\sqrt 3 }}{3}\)
\(\tan \left( {x + \frac{\pi }{3}} \right) = \frac{{\tan x + \tan \frac{\pi }{3}}}{{1 - \tan x \cdot \tan \frac{\pi }{3}}} = \frac{{\frac{{ - \sqrt 3 }}{3} + \sqrt 3 }}{{1 - \frac{{ - \sqrt 3 }}{3} \cdot \sqrt 3 }} = \frac{{\sqrt 3 }}{3}\).
Đáp án: a) Đúng; b) Sai; c) Đúng; d) Đúng.