Kết quả lim(x+1)/(2x^3+2) bằng:

7/50

Kết quả \(\mathop {\lim }\limits_{x \to - 1} \frac{{x + 1}}{{2{x^3} + 2}}\) bằng:

\(0\).

\( - \frac{1}{2}\).

\(\frac{1}{6}\).

\(\frac{1}{2}\).

Giải thích

Ta có:

\(\mathop {\lim }\limits_{x \to - 1} \frac{{x + 1}}{{2{x^3} + 2}} = \mathop {\lim }\limits_{x \to - 1} \frac{{x + 1}}{{2\left( {{x^3} + 1} \right)}} = \mathop {\lim }\limits_{x \to - 1} \frac{{x + 1}}{{2\left( {x + 1} \right)\left( {{x^2} - x + 1} \right)}} = \mathop {\lim }\limits_{x \to - 1} \frac{1}{{2\left( {{x^2} - x + 1} \right)}} = \frac{1}{{2.3}} = \frac{1}{6}.\)