Hãy xác định hệ thức sai:
Chọn C
A. \(\sin x.{\rm{co}}{{\rm{s}}^3}x - {\rm{cos }}x{\sin ^3}x = \sin x.{\rm{cos}}x({\rm{co}}{{\rm{s}}^2}x - {\sin ^2}x) = \frac{1}{2}\sin 2x.{\rm{cos2}}x = \frac{{\sin 4x}}{4}\).
B. \({\sin ^4}x + {\rm{co}}{{\rm{s}}^4}x = 1 - 2{\sin ^2}x.{\rm{co}}{{\rm{s}}^2}x = 1 - \frac{1}{2}{\sin ^2}2x = 1 - \frac{1}{2}(\frac{{1 - {\rm{cos}}4x}}{2}) = \frac{{3 + {\rm{cos}}4x}}{4}\).
C. \(\frac{{1 + \sin x}}{{{\rm{cos }}x}} = \frac{{1 - {\rm{cos(}}\frac{\pi }{2}{\rm{ + x)}}}}{{\sin {\rm{(}}\frac{\pi }{2}{\rm{ + x)}}}} = \frac{{2{{\sin }^2}(\frac{\pi }{4}{\rm{ + }}\frac{{\rm{x}}}{2})}}{{2\sin {\rm{(}}\frac{\pi }{2}{\rm{ + x)cos}}(\frac{\pi }{4}{\rm{ + }}\frac{{\rm{x}}}{2})}} = \tan (\frac{\pi }{4} + \frac{x}{2})\).
D. \({\cot ^2}x + {\tan ^2}x = \frac{{{\rm{co}}{{\rm{s}}^2}x}}{{{{\sin }^2}x}} + \frac{{{{\sin }^2}x}}{{{\rm{co}}{{\rm{s}}^2}x}} = \frac{{{\rm{co}}{{\rm{s}}^4}x + {{\sin }^4}x}}{{{\rm{co}}{{\rm{s}}^2}x.{{\sin }^2}x}} = \frac{{\frac{{3 + {\rm{cos}}4x}}{4}}}{{\frac{{1 - {\rm{cos}}4x}}{8}}} = \frac{{2\cos 4x + 6}}{{1 - {\rm{cos}}4x}}\).