Giải phương trình : a. |2x-5|=4
Giải thích
a)2x−5=41+)x≥52⇒1⇔2x−5=4⇔x=92(tm)+)x<52⇒1⇔5−2x=4⇔x=−12(tm)
b)5x2−3x5+3x+14<x2x+12−32⇔45x2−3x+53x+120<10x2x+1−3.1020⇔20x2−12x+15x+5<20x2+10x−30⇔7x>35⇔x>5
a)2x−5=41+)x≥52⇒1⇔2x−5=4⇔x=92(tm)+)x<52⇒1⇔5−2x=4⇔x=−12(tm)
b)5x2−3x5+3x+14<x2x+12−32⇔45x2−3x+53x+120<10x2x+1−3.1020⇔20x2−12x+15x+5<20x2+10x−30⇔7x>35⇔x>5