Giải các bất phương trình sau: a) (4x − 1)/9 < (5 − 3x)/6;

a) \(\frac{{4x - 1}}{9} < \frac{{5 - 3x}}{6}\)

\(\frac{{2\left( {4x - 1} \right)}}{{18}} < \frac{{3\left( {5 - 3x} \right)}}{{18}}\)

\(8x - 2 < 15 - 9x\)

\(\begin{array}{l}8x + 9x < 15 + 2\\17x < 17\\x < 1\end{array}\)

Vậy \(x < 1\).

b)\(\frac{{2x - 5}}{{18}} < \frac{{4x + 3}}{{10}}\)

\(\begin{array}{l}\frac{{5\left( {2x - 5} \right)}}{{90}} < \frac{{9\left( {4x + 3} \right)}}{{90}}\\10x - 25 < 36x + 27\end{array}\)

\(\begin{array}{l}10x - 36x < 27 + 25\\ - 26x < 52\\x > \frac{{52}}{{ - 26}}\\x > - 2\end{array}\)

Vậy \(x > - 2\).