Giá trị của m là

Đáp án đúng là: A

$\begin{array}{l}0,25\left\{\begin{array}{l}{\mathrm{n}}_{\mathrm{NO}}=\mathrm{x}\mathrm{mol}\\ {\mathrm{n}}_{{\mathrm{N}}_2\mathrm{O}}=\mathrm{y}\mathrm{mol}\end{array}\right.\to \left\{\begin{array}{l}\mathrm{x}+\mathrm{y}=0,25\\ \frac{30\mathrm{x}+44\mathrm{y}}{0,25}=2.16,4\end{array}\right.\Rightarrow \left\{\begin{array}{l}\mathrm{x}=0,2\\ \mathrm{y}=0,05\end{array}\right.;\\ \mathrm{SPK}\left\{\begin{array}{l}\mathrm{NO}:0,2\mathrm{mol}\\ {\mathrm{N}}_2\mathrm{O}:0,05\mathrm{mol}\end{array}\right.;{\mathrm{NH}}_4{\mathrm{NO}}_3:\mathrm{a}\mathrm{mol}\end{array}$

$\begin{array}{l}\stackrel{\mathrm{BTNT}.\mathrm{nitrogen}}{\to }0,95.1,5=0,2+0,05.2+0,2.3+0,05.8+2\mathrm{a}+8\mathrm{a}\\ \to \mathrm{a}=0,0125\mathrm{mol}\end{array}$

$\stackrel{\mathrm{BTKL}}{\to }\mathrm{m}=29+62(0,2.3+0,05.8+0,0125.8)+0,0125.80=98,2\mathrm{g}$