Bài tập Toán lớp 5 Phép cộng phân số khác mẫu số có đáp án

\(\frac{2}{{17}} + \frac{1}{3} = \) ...

3/4

\(\frac{2}{{17}} + \frac{1}{3} = \) ...

\[\frac{1}{{16}} + \frac{3}{5} = \]...

\(\frac{5}{{14}} + \frac{2}{9} = \)...

\[\frac{3}{{19}} + \frac{4}{7} = \]...

\(\frac{1}{5} + \frac{6}{{11}} = \)...

\(\frac{4}{{15}} + \frac{1}{8} = \)...

\(\frac{2}{3} + \frac{5}{{16}} = \)...

\(\frac{3}{7} + \frac{2}{{13}} = \)...

\(\frac{1}{9} + \frac{4}{{17}} = \)...

\(\frac{5}{{12}} + \frac{3}{{10}} = \)...

\(\frac{2}{{11}} + \frac{5}{6} = \)...

\(\frac{1}{4} + \frac{7}{{15}} = \)...

\(\frac{3}{8} + \frac{4}{{19}} = \)...

\(\frac{6}{7} + \frac{1}{{12}} = \)...

\[\frac{2}{5} + \frac{3}{{14}} = \]...

\(\frac{1}{{13}} + \frac{5}{9} = \)...

\(\frac{4}{{11}} + \frac{2}{{15}} = \)...

\[\frac{3}{5} + \frac{1}{{16}} = \]...

\(\frac{2}{7} + \frac{4}{{13}} = \)...

\(\frac{1}{3} + \frac{6}{{17}} = \)...

\(\frac{5}{8} + \frac{3}{{11}} = \)...

\(\frac{2}{9} + \frac{4}{5} = \)...

\(\frac{1}{7} + \frac{5}{{12}} = \)

\(\frac{3}{{10}} + \frac{2}{{13}} = \)...

\(\frac{4}{9} + \frac{1}{{14}} = \)...

\(\frac{2}{3} + \frac{5}{7} = \)...

\(\frac{1}{5} + \frac{3}{8} = \)...

\(\frac{4}{{13}} + \frac{2}{{11}} = \)...

\(\frac{3}{7} + \frac{1}{9} = \)...

\(\frac{5}{{16}} + \frac{2}{5} = \)...

\(\frac{1}{{11}} + \frac{4}{{15}} = \)...

\(\frac{2}{{17}} + \frac{3}{4} = \)...

\(\frac{5}{9} + \frac{1}{{10}} = \)...

\(\frac{3}{{18}} + \frac{2}{6} = \)...

\(\frac{1}{3} + \frac{4}{{11}} = \)...

\(\frac{2}{5} + \frac{5}{{13}} = \)...

\[\frac{3}{8} + \frac{1}{{12}} = \]...

\(\frac{4}{7} + \frac{2}{9} = \)...

\(\frac{1}{{15}} + \frac{3}{7} = \)...

\(\frac{5}{{11}} + \frac{2}{3} = \)...

0/3000 ký tự
Giải thích

\(\begin{array}{l}\frac{2}{{17}} + \frac{1}{3} = \frac{6}{{51}} + \frac{{17}}{{51}}\\ = \frac{{23}}{{51}}\end{array}\)

\(\begin{array}{l}\frac{1}{{16}} + \frac{3}{5} = \frac{5}{{80}} + \frac{{48}}{{80}}\\ = \frac{{53}}{{80}}\end{array}\)

\(\begin{array}{l}\frac{5}{{14}} + \frac{2}{9} = \frac{{45}}{{126}} + \frac{{28}}{{126}}\\ = \frac{{73}}{{126}}\end{array}\)

\[\begin{array}{l}\frac{3}{{19}} + \frac{4}{7} = \frac{{21}}{{133}} + \frac{{76}}{{133}}\\ = \frac{{97}}{{133}}\end{array}\]

\(\begin{array}{l}\frac{1}{5} + \frac{6}{{11}} = \frac{{11}}{{55}} + \frac{{30}}{{55}}\\ = \frac{{41}}{{55}}\end{array}\)

\(\begin{array}{l}\frac{4}{{15}} + \frac{1}{8} = \frac{{32}}{{120}} + \frac{{15}}{{120}}\\ = \frac{{47}}{{120}}\end{array}\)

\(\begin{array}{l}\frac{2}{3} + \frac{5}{{16}} = \frac{{32}}{{48}} + \frac{{15}}{{48}}\\ = \frac{{47}}{{48}}\end{array}\)

\(\begin{array}{l}\frac{3}{7} + \frac{2}{{13}} = \frac{{39}}{{91}} + \frac{{14}}{{91}}\\ = \frac{{53}}{{91}}\end{array}\)

\(\begin{array}{l}\frac{1}{9} + \frac{4}{{17}} = \frac{{17}}{{153}} + \frac{{36}}{{153}}\\ = \frac{{53}}{{153}}\end{array}\)

\(\begin{array}{l}\frac{5}{{12}} + \frac{3}{{10}} = \frac{{25}}{{60}} + \frac{{18}}{{60}}\\ = \frac{{43}}{{60}}\end{array}\)

\(\begin{array}{l}\frac{2}{{11}} + \frac{5}{6} = \frac{{12}}{{66}} + \frac{{55}}{{66}}\\ = \frac{{67}}{{66}}\end{array}\)

\(\begin{array}{l}\frac{1}{4} + \frac{7}{{15}} = \frac{{15}}{{60}} + \frac{{28}}{{60}}\\ = \frac{{43}}{{60}}\end{array}\)

\(\begin{array}{l}\frac{3}{8} + \frac{4}{{19}} = \frac{{57}}{{152}} + \frac{{32}}{{152}}\\ = \frac{{89}}{{152}}\end{array}\)

\(\begin{array}{l}\frac{6}{7} + \frac{1}{{12}} = \frac{{72}}{{84}} + \frac{7}{{84}}\\ = \frac{{79}}{{84}}\end{array}\)

\[\begin{array}{l}\frac{2}{5} + \frac{3}{{14}} = \frac{{28}}{{70}} + \frac{{15}}{{70}}\\ = \frac{{43}}{{70}}\end{array}\]

\(\begin{array}{l}\frac{1}{{13}} + \frac{5}{9} = \frac{9}{{117}} + \frac{{65}}{{117}}\\ = \frac{{74}}{{117}}\end{array}\)

\(\begin{array}{l}\frac{4}{{11}} + \frac{2}{{15}} = \frac{{60}}{{165}} + \frac{{22}}{{165}}\\ = \frac{{82}}{{165}}\end{array}\)

\[\begin{array}{l}\frac{3}{5} + \frac{1}{{16}} = \frac{{48}}{{80}} + \frac{5}{{80}}\\ = \frac{{53}}{{80}}\end{array}\]

\(\begin{array}{l}\frac{2}{7} + \frac{4}{{13}} = \frac{{26}}{{91}} + \frac{{28}}{{91}}\\ = \frac{{54}}{{91}}\end{array}\)

\(\begin{array}{l}\frac{1}{3} + \frac{6}{{17}} = \frac{{17}}{{51}} + \frac{{18}}{{51}}\\ = \frac{{35}}{{51}}\end{array}\)

\(\begin{array}{l}\frac{5}{8} + \frac{3}{{11}} = \frac{{55}}{{88}} + \frac{{24}}{{88}}\\ = \frac{{79}}{{88}}\end{array}\)

\(\begin{array}{l}\frac{2}{9} + \frac{4}{5} = \frac{{10}}{{45}} + \frac{{36}}{{45}}\\ = \frac{{46}}{{45}}\end{array}\)

\(\begin{array}{l}\frac{1}{7} + \frac{5}{{12}} = \frac{{12}}{{84}} + \frac{{35}}{{84}}\\ = \frac{{47}}{{84}}\end{array}\)

\(\begin{array}{l}\frac{3}{{10}} + \frac{2}{{13}} = \frac{{39}}{{130}} + \frac{{20}}{{130}}\\ = \frac{{59}}{{130}}\end{array}\)

\(\begin{array}{l}\frac{4}{9} + \frac{1}{{14}} = \frac{{56}}{{126}} + \frac{9}{{126}}\\ = \frac{{65}}{{126}}\end{array}\)

\(\begin{array}{l}\frac{2}{3} + \frac{5}{7} = \frac{{14}}{{21}} + \frac{{15}}{{21}}\\ = \frac{{29}}{{21}}\end{array}\)

\(\begin{array}{l}\frac{1}{5} + \frac{3}{8} = \frac{8}{{40}} + \frac{{15}}{{40}}\\ = \frac{{23}}{{40}}\end{array}\)

\(\begin{array}{l}\frac{4}{{13}} + \frac{2}{{11}} = \frac{{44}}{{143}} + \frac{{26}}{{143}}\\ = \frac{{70}}{{143}}\end{array}\)

\(\begin{array}{l}\frac{3}{7} + \frac{1}{9} = \frac{{27}}{{63}} + \frac{7}{{63}}\\ = \frac{{34}}{{63}}\end{array}\)

\(\begin{array}{l}\frac{5}{{16}} + \frac{2}{5} = \frac{{25}}{{80}} + \frac{{32}}{{80}}\\ = \frac{{57}}{{80}}\end{array}\)

\(\begin{array}{l}\frac{1}{{11}} + \frac{4}{{15}} = \frac{{15}}{{165}} + \frac{{44}}{{165}}\\ = \frac{{59}}{{165}}\end{array}\)

\(\begin{array}{l}\frac{2}{{17}} + \frac{3}{4} = \frac{8}{{68}} + \frac{{51}}{{68}}\\ = \frac{{59}}{{68}}\end{array}\)

\(\begin{array}{l}\frac{5}{9} + \frac{1}{{10}} = \frac{{50}}{{90}} + \frac{9}{{90}}\\ = \frac{{59}}{{90}}\end{array}\)

\(\begin{array}{l}\frac{3}{{18}} + \frac{2}{6} = \frac{3}{{18}} + \frac{6}{{18}}\\ = \frac{9}{{18}} = \frac{1}{2}\end{array}\)

\(\begin{array}{l}\frac{1}{3} + \frac{4}{{11}} = \frac{{11}}{{33}} + \frac{{12}}{{33}}\\ = \frac{{23}}{{33}}\end{array}\)

\(\begin{array}{l}\frac{2}{5} + \frac{5}{{13}} = \frac{{26}}{{65}} + \frac{{25}}{{65}}\\ = \frac{{51}}{{65}}\end{array}\)

\[\begin{array}{l}\frac{3}{8} + \frac{1}{{12}} = \frac{9}{{24}} + \frac{2}{{24}}\\ = \frac{{11}}{{24}}\end{array}\]

\(\begin{array}{l}\frac{4}{7} + \frac{2}{9} = \frac{{36}}{{63}} + \frac{{14}}{{63}}\\ = \frac{{50}}{{63}}\end{array}\)

\(\begin{array}{l}\frac{1}{{15}} + \frac{3}{7} = \frac{7}{{105}} + \frac{{45}}{{105}}\\ = \frac{{52}}{{105}}\end{array}\)

\(\begin{array}{l}\frac{5}{{11}} + \frac{2}{3} = \frac{{15}}{{33}} + \frac{{22}}{{33}}\\ = \frac{{37}}{{33}}\end{array}\)