Bài tập Toán lớp 5 Nhân một số thập phân với một số tự nhiên có đáp án

Đặt tính rồi tính 23,4 × 2 = .... 56,78 × 3 = .... 89,12 × 6 = .... 34,56 × 7 = .... 83,45 × 2 = .... 56,7 × 4 = .... 29,4 × 53 = .... 56,7 × 41 = .... 78,23 × 27 = .... 45,6 × 89 =

1/5

Đặt tính rồi tính

23,4 × 2 = ....

 

56,78 × 3 = ....

 

89,12 × 6 = ....

 

34,56 × 7 = ....

 

83,45 × 2 = ....

 

56,7 × 4 = ....

 

29,4 × 53 = ....

 

56,7 × 41 = ....

 

78,23 × 27 = ....

 

45,6 × 89 = ....

 

83,45 × 19 = ....

 

29,3 × 67 = ....

 

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Giải thích

23,4 × 2 = 46,8

\(\begin{array}{l}\underline { \times \begin{array}{*{20}{c}}{23,4}\\{\,\,\,\,\,\,\,2}\end{array}} \\\,\,\,46,8\end{array}\)

56,78 × 3 = 170,34

\(\begin{array}{l}\underline { \times \begin{array}{*{20}{c}}{56,78}\\{\,\,\,\,\,\,\,\,\,\,3}\end{array}} \\170,34\end{array}\)

89,12 × 6 = 534,72

\(\begin{array}{l}\underline {\, \times \begin{array}{*{20}{c}}{89,12}\\{\,\,\,\,\,\,\,\,6}\end{array}} \\\,534,72\end{array}\)

34,56 × 7 = 241,92

\(\begin{array}{l}\underline { \times \begin{array}{*{20}{c}}{34,56}\\{\,\,\,\,\,\,\,\,\,\,7}\end{array}} \\241,92\end{array}\)

83,45 × 2 = 166,9

\(\begin{array}{l}\underline { \times \begin{array}{*{20}{c}}{83,45}\\{\,\,\,\,\,\,\,\,\,\,2}\end{array}} \\166,9\end{array}\)

56,7 × 4 = 226,8

\(\begin{array}{l}\underline { \times \begin{array}{*{20}{c}}{56,7}\\{\,\,\,\,\,\,\,4}\end{array}} \\226,8\end{array}\)

29,4 × 53 = 1558,2

\(\begin{array}{l}\underline {\,\, \times \begin{array}{*{20}{c}}{29,4}\\{\,\,\,\,53}\end{array}} \\\,\,\,\,\,\,882\\\underline {1470\,\,\,\,\,\,\,} \\1558,2\end{array}\)

56,7 × 41 = 2324,7

\(\begin{array}{l}\underline {\,\, \times \begin{array}{*{20}{c}}{56,7}\\{\,\,\,\,\,41}\end{array}} \\\,\,\,\,\,\,\,\,567\\\underline {\,\,2268\,\,\,\,\,\,\,} \\2324,7\end{array}\)

78,23 × 27 = 2112,21

\(\begin{array}{l}\underline {\,\, \times \begin{array}{*{20}{c}}{78,23}\\{\,\,\,\,\,\,\,27}\end{array}} \\\,\,\,\,54761\\\underline {\,15646\,\,\,\,\,\,\,} \\2112,21\end{array}\)

45,6 × 89 = 4058,4

\(\begin{array}{l}\underline {\,\, \times \begin{array}{*{20}{c}}{45,6}\\{\,\,\,\,\,89}\end{array}} \\\,\,\,\,4104\\\underline {\,3648\,\,\,\,\,\,\,} \\4058,4\end{array}\)

83,45 × 19 = 1585,55

\(\begin{array}{l}\underline {\,\, \times \begin{array}{*{20}{c}}{83,45}\\{\,\,\,\,\,\,\,19}\end{array}} \\\,\,\,75105\\\underline {\,\,\,8345\,\,\,\,\,\,\,} \\1585,55\end{array}\)

29,3 × 67 = 1963,1

\(\begin{array}{l}\underline {\,\, \times \begin{array}{*{20}{c}}{29,3}\\{\,\,\,\,67}\end{array}} \\\,\,\,\,2051\\\underline {\,1758\,\,\,\,\,\,\,} \\1963,1\end{array}\)