Cho \[y = \ln \left( {{e^{f\left( {2x - 1} \right)}} - 1} \right)\], tính y’:

\[\frac{{2f'\left( {2x - 1} \right)}}{{{e^{f\left( {2x - 1} \right)}} - 1}}\]

\[\frac{{{e^{f\left( {2x - 1} \right)}}f'\left( {2x - 1} \right)}}{{{e^{f\left( {2x - 1} \right)}} - 1}}\]

\[\frac{{2.{e^{f\left( {2x - 1} \right)}}f'\left( {2x - 1} \right)}}{{{e^{f\left( {2x - 1} \right)}} - 1}}\]

\[ - \frac{{2.{e^{f\left( {2x - 1} \right)}}f'\left( {2x - 1} \right)}}{{{e^{f\left( {2x - 1} \right)}} - 1}}\]