Cho tích phân - 1^0 f( x )dx = 3, tích phân 0^3 f( x )dx = 3.Tích phân 1^3 f( x )dx bằng

16/25

Cho \(\mathop \smallint \limits_{ - 1}^0 f\left( x \right)dx = 3\mathop \smallint \limits_0^3 f\left( x \right)dx = 3.\) Tích phân \(\mathop \smallint \limits_1^3 f\left( x \right)dx\) bằng

\(6\)

\(4\)

\(2\)

\(0\)

Giải thích

Chọn D

Có \(\mathop \smallint \limits_{ - 1}^0 f\left( x \right)dx = 3;\;\mathop \smallint \limits_0^3 f\left( x \right)dx = 1;\;{\rm{\;}}\mathop \smallint \limits_{ - 1}^3 f\left( x \right)dx = \mathop \smallint \limits_{ - 1}^0 f\left( x \right)dx + \mathop \smallint \limits_0^3 f\left( x \right)dx = 3 + 1 = 4\)