Cho lim x → 3 f ( x ) = − 2 . Tính lim x → 3 [ f ( x ) + 4 x − 1 ] .
Giải thích
\(\mathop {\lim }\limits_{x \to 3} \left[ {f\left( x \right) + 4x - 1} \right]\)\( = \mathop {\lim }\limits_{x \to 3} f\left( x \right) + \mathop {\lim }\limits_{x \to 3} \left( {4x - 1} \right)\)\( = - 2 + 11 = 9\).
Trả lời: 9.