291 Bài trắc nghiệm Hàm số Cực hay có lời giải chi tiết (P7)

Cho hàm số y = f(x) có đạo hàm trên R và có đồ thị như hình vẽ

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Cho hàm số y = f(x) có đạo hàm trên R và có đồ thị như hình vẽ. Đặt hàm số y=g(x)=f(2x3+x-1)+m. Tìm m để max[0;1] g(x)=-10.

m= -1

m= 3

m= -12

m= -13

Giải thích

Đáp án D

 Hàm số BrchGsEq60uHqmTd75rI2ndiuA4Dhcvg1aM9hhQwTTp8ASZRwG85zDlaN8BS-gBz6CWF1AZ5a7CTMppUmOSEjh1yElsnc8ObrjcjcicVGhwH5uWbvG542xgWDWDG7VILvb114E1BiDBxd5u0DA có dạng: k5ocyE4taH64DnYC5_Rft6Ozf5Um8-oT3eeBgrAeP-n2YQDWSepnlcm_fo6NXsmQq658FVbCpFhSp7G9_1W2Xl8CBl7R5oUb9faFgilwp4gZn9NFjOb1pIfjzrjM20zDSY9PlXKkk_zr1FRQ-g

Ta có: RYkZ28RcYjHCsa2wqbxSREvCSjC8gWYkUcDTPBkCI99Z0vBxIk6gZJf6zV5PBp0DlZhHMhJcjhmdBkIXf9WUmoLl-6IIRoDD4eGWBthf4eiqXJ0SdaV28JYGJhssSeh4oSjr4nmK5kZq3KDgxQ.

Theo đồ thị, hai điểm JRi5c55tqkB5Z20RfQgYtV3MFfm__Mv_1eKNhxpi6acqCZ2bLTsDLRmTA4LIWH9sq0Y8HXJr1e8f1s3JCVXzn1JFBKHIH-YyZKhLBjcZgv1Eoppn60JA3P6-ea_Ikl_GOHNp9r4oAQGCYCtBgQlPXyOEE_0tWojHzbCKk1PihveLWl_36QuUspRr8kelLiP8k9gvXvWyOrkGeNEKPn4zDSA7U1KlgcrYvjguWSI5P_UoysCddHGToZgqDGdivssrkIsF4ql4F_R-ft8_TdkY_1zj2pAxirrgywFw là hai điểm cực trị của đồ thị hàm số n4YzRM0-GgNxQ10THRsqeg2IMJvTnl3IZUXJhRPnqW6iQoqArVlO5qnAMM9BAqi8uqdMp9rLyrszjyMHIXzdarMqnHKjJYpN1i6-0kKBMqkUebfxtFJxUiudDas7LorcovAPGeIceSqpTZlRdw.

Ta có hệ: cI5UN4HSEajRBdy_dGSsiO1jm8BwR3lVbZFAO3g07xj0FRe4dJliFgieJ-fBhpzX69YrZmdyucXYqDpz6vvKNoy9VCy8dMdBx7_2z7BT0itm1hj4tI8HpN56dbNkO8wtSDz0kE4OzY9FYqDsmA4RgyrHr6T3bZGSbwZ8i74k0FabOKtLKQ6dobG-VdWQgombNOCc6574p2EzAX6jOsJOKXrgw_aff_cQxsuKXeJ5RA5yyuVKqSvATNTQcJSn0HIjvRQtS_2L8bPq_35GLjtSBnZd__ykF21y3Cpg .

Do đó: 0BkxFVbnrxu4rxIhCxIFs-6WJMvziS9Iv3n2BgiNLHpiVJwaIW6xLyrwoFjUbJ5DiP0C0T9lj2tm2RVrQQr3kNoTnJDhVHbCvmCfAY7twLHqhZx01fbU8vLfQeFox83WJENlB9qRjOEfV6vUtw.

Ta có:nsW4NPVs90TOECHErsuNa0z9ucQAXkW4BBq1bIE_YNV9SBMKNYdcFW5ukOEXH8id9QYePGorYQ3nzahAGZOPTRP2drHEei-3uodqhu-xVVXIVZQMB9FoAdXP8Rn3AAFEYKqT1NYQy98X1Et7Xw;

g4w2U2viWBu7fL055fbqvNtFV1CfM97TRc1oiU4hB_B_tzIOaAjt9DqYY_9Ma1_dvRkZ35YAHC2YXcq2KXwulFHvzK2RXDbH5QQANbdTcrUINhpRMlQc-5iyFRZsuFpZy_LyRpHv0ejeDL-bbw

Lại có: fVpSkhq5TL7kjmZDsVJOz6yANRlHumrbaaGTdsxOlqELIZpYi0HRNCmx0U517utqGzxRXnj6V1LKMC-6G02k2CjYrIVi0sqOQvLJt_LpGb8bGSrmjByfRRufxVj_OQR7xAV1gQrvZIgAZniPjg

NpTAlPERq8jaJGs64yjX5lxjkNDXK1T6DAu_q0s1FoiFGdiV1HTEM0_LDuthqna_FyzjA6XKZ6MzylfeqLAlEQTD8agV0Do3S3aOofDp8tJpA605Fn_ZhJg8TsKOIAOTGNlEoaBen8YW3Fyo6g

8cA6xQyH8eTYV_Cqghf7qV3DjF5nVQcVwZ5FuQFVbb1rQVvF9Xm-W8ZSJ6kWVCdfc8j4jKV6uJq7cG8SvZJOcJvJR3tRsymuh2qyWxLefudQx59VJmkZZyOZoietYxg8xEPj2aUSpg-OXqTM7g

với gm2ZIbBUSj8dT8cLYK0sgbRb8A54B8F1rHvlyWX4UHKqL7t6_28x13ra99IWYecZjkkmdGLHT6gixBTjC-k5nc0yvXaXG-1WqAcqxulOc4_3Mumdg7Z6FyEpi8XNh_k27_pxSAxrTu0HAYknrg và thỏa 7RIH_uf4LcYoG1Ame_R5pmiF5zusqJxuLLydX5eGw2P7R--VtRQVykDApKYuTEgURSOr9WGVOu1Hyd7HpKPObFuDf4CvEdLkV8lV9yFH8kx2T8VS9DBp2a2EdtdkJc7cziaI0ouMs9Bw-zY6hA.

Ta có: W1VyWj9SAA9PrKYUczjZPY73TQ3gdcZMMRPBpIVTDrLYOkRVKlBmbO2Pp6_wOdnn0eiIwa3Kj5-yo9j0q8CaMMDfrOZPiJiLAK9yF2w6PDWiLRNYoY-zJmaQxWGiPWxdVwO6Tp2YL9NmL7v1DQ

_gr6rPvw4ITbyBQvWo2xmFvIqiEWQtGZtLyfqfCRcx0MrpBGq9RDI-RiMXjLMJkMJ6jqrXTAAlY0GIZqfryMURMHj2eOAU1V94Y3FL_9zmZW4XbZdxXoap1oPtjYdcxpjUcXBFystxZqwv_s4g

vzP0Bb9jk41O8oWC_0pAefCiEGvBxV046NNwn6KVtyd_taeKbj_rndxVwVx96AfMmc3HWqiB7Q__zcuspIb_rLV2tdDR9TILqJGLS9zJJNgCLlG4n4vTqilFSETUND0pNE_5Bk5uEPyxAB-w2w.

Theo đề bài, ta có: mAn7HtySA36vTSQKBvE2klDzZkEwL-khaY6aTTAdwhXWdOVEXLKlpvFKZlEc-Kr-n4nFmfW5M8LJUkhVadp2k-hcj-_qTQ00e5CQ48VUxoWpuJmbBZWoJDZFlWb5uxfwCld-9Bv3DkME5D_igQ.