Cho các hợp chất: C2H6; C2H2; C2H4O2; C2H6O; C6H12O6.
Giải thích
Đáp án B
%C(C2H6)=12.212.2+6.100%=80%%C(C2H2)=12.212.2+2.100%=92,31%%C(C2H4O2)=12.212.2+4+16.2.100%=40%
%C(C2H6O)=12.212.2+6+16.100%=52,14%%C(C6H12O6)=12.612.6+12+16.6.100%=40%
Đáp án B
%C(C2H6)=12.212.2+6.100%=80%%C(C2H2)=12.212.2+2.100%=92,31%%C(C2H4O2)=12.212.2+4+16.2.100%=40%
%C(C2H6O)=12.212.2+6+16.100%=52,14%%C(C6H12O6)=12.612.6+12+16.6.100%=40%