Cellulose tác dụng với acetic anhydride thu được cellulose triacetate theo phương trình sau: [ C 6 H 7 O 2 ( O H ) 3 ] n   +   3 n ( C H 3

Đáp án: 1780

1 tấn bông có 990 kg cellulose.

$\begin{array}{l}{\text{[}{\text{C}}_{\text{6}}{\text{H}}_{\text{7}}{\text{O}}_{\text{2}}{\text{(}\text{O}\text{H}\text{)}}_{\text{3}}\text{]}}_{\text{n}}\text{+}\text{3}\text{n}{\text{(}\text{C}{\text{H}}_{\text{3}}\text{C}\text{O}\text{)}}_{\text{2}}\text{O}\underset{}{\overset{}{\to }}{\text{[}{\text{C}}_{\text{6}}{\text{H}}_{\text{7}}{\text{O}}_{\text{2}}{\text{(}\text{O}\text{C}\text{O}\text{C}{\text{H}}_{\text{3}}\text{)}}_{\text{3}}\text{]}}_{\text{n}}\text{+}\text{3}\text{n}\text{C}{\text{H}}_{\text{3}}\text{C}\text{O}\text{O}\text{H}\\ \text{1}\text{6}\text{2}\text{n}\text{2}\text{8}\text{8}\text{n}\text{g}\text{a}\text{m}\\ \text{9}\text{9}\text{0}\text{k}\text{g}\end{array}$

Khối lượng tơ thu được là:

$m=\frac{990.288n.0,91}{162n.0,90}=1780$ kg.