b) ( 45 × 46 × 47 × 48) × (51 × 52 – 49 × 48) × ( 45 × 128 – 90 × 64)
Giải thích
b) ( 45 × 46 × 47 × 48) × (51 × 52 – 49 × 48) × ( 45 × 128 – 90 × 64)
Nhận xét: 45 × 128 – 90 × 64 = 45 × ( 2× 64) – 90 × 64 = (45 × 2)× 64) – 90 × 64
= 90 × 64 – 90 × 64 = 0 (0,2đ)
Vậy: ( 45 × 46 × 47 × 48) × (51 × 52 – 49 × 48) × ( 45 × 128 – 90 × 64)
= ( 45 × 46 × 47 × 48) × (51 × 52 – 49 × 48) × 0 = 0