a) Rút gọn biểu thức A;
Giải thích
a) Với x≠−12 ; x≠−32, ta có:
A=22x+3+32x+1−6x+52x+32x+1 =22x+12x+32x+1+32x+32x+32x+1−6x+52x+32x+1 =22x+1+32x+3−6x+52x+32x+1 =4x+2+6x+9−6x−52x+32x+1 =4x+62x+32x+1=22x+32x+32x+1=22x+1.
a) Với x≠−12 ; x≠−32, ta có:
A=22x+3+32x+1−6x+52x+32x+1 =22x+12x+32x+1+32x+32x+32x+1−6x+52x+32x+1 =22x+1+32x+3−6x+52x+32x+1 =4x+2+6x+9−6x−52x+32x+1 =4x+62x+32x+1=22x+32x+32x+1=22x+1.